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UPSC NDA II 2023 Mathematics Solved Paper

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Consider the following for the next three (03) items that follow :
Let (1+x)n=1+T1x+T2x2+T3x3+...+Tnxn.

[NDA II 2023]

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Question : 39

Total: 120

What is 1−T1+2T2−3T3+...+(−1)nnTn equal to?

0
−2n−1
n2n−1
1

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