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UPSC NDA II 2023 Mathematics Solved Paper

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Consider the following for the next three (03) items that follow :
Let (1+x)n=1+T1x+T2x2+T3x3+...+Tnxn.

[NDA II 2023]

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Question : 38

Total: 120

What is T1+2T2+3T3+...+nTn equal to

0
1
2n
n2n−1

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