3x3−26x2+52x−24=0 Roots are in GP. Let roots be ‌
a
r
,a, ar So, ‌‌‌
a
r
⋅a⋅ar=‌
24
3
a3=8⇒a=2 Hence, 2 is root and (x−2) is a factor of ‌3x3−26x2+52x−24 ‌ So, ‌(x−2)(3x2−20x+12)=0 (x−2)(x−6)(3x−2)‌‌=0 ⇒‌‌x‌‌=2,6,‌