f(x)‌‌=x2+ax+2 g(x)‌‌=x2+2x+a f(x)−g(x)‌‌=(a−2)x+(2−a)=0 x‌‌=1 ‌ So, 1 is the common root for both ‌ f(1)‌‌=a+3=0 g(1)‌‌=a+3=0 h(x)‌‌=f(x)+g(x) ‌‌=2x2+(a+2)x+(a+2) ‌‌=2x2−x−1 ‌‌=(2x+1)(x−1) Roots ⇒x=−‌