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Question : 3 of 40

Marks: +1, -0

The circumference of the base of a right circular cylinder is 13.2 m and sum of its radius and height is 3m. Find the radius and total surface area of the cylinder.

1.5 m; 35.5 $m^2$
2m; 37.6 $m^2$
2.1 m; 39.6 $m^2$
2.5m; 40 $m^2$

Solution: 👈: Video Solution

Concept:

For a right circular cylinder, circumference

=2\pi r

and total surface area

=2\pi r(h+r)

.

Explanation:

Given

2\pi r = 13.2\ \mathrm{m}

.

So,

r = \frac{13.2 \times 7}{2 \times 22} = 2.1\ \mathrm{m}

.

Given

r + h = 3\ \mathrm{m}

.

Thus,

h = 3 - 2.1 = 0.9\ \mathrm{m}

.

Total surface area

= 2\pi r(h+r)

.

= 13.2 \times 3 = 39.6\ \mathrm{m}^2

.

Answer:

Radius

= 2.1\ \mathrm{m}

; total surface area

= 39.6\ \mathrm{m}^2

.

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