MHTCET 16 Apr 2026 Shift 2 Paper

Concept:Strong oxidising agents like $\mathrm{CrO}_{3}$ can cleave the carbon–carbon bond adjacent to a ketone carbonyl group on heating.Explanation:Acetone is the simplest ketone with the formula $\mathrm{CH}_{3}\mathrm{COCH}_{3}$.Ketones are normally resistant to oxidation under mild conditions.However, on heating with a powerful oxidising agent such as $\mathrm{CrO}_{3}$, oxidative cleavage occurs.The bond between the carbonyl carbon and the neighbouring methyl carbon breaks.Each cleaved carbon fragment gets oxidised to a carboxylic acid.For acetone, this cleavage yields two identical fragments that finally produce acetic acid.The balanced reaction is:$$\mathrm{CH}_{3}\mathrm{COCH}_{3} \xrightarrow[\text{heat}]{\mathrm{CrO}_{3}} 2\,\mathrm{CH}_{3}\mathrm{COOH}$$Thus, the main product formed is acetic acid.Among the given options, acetic acid corresponds to option A.Answer:Option A: Acetic acid