(c) Given A, = ₹ 944, T = 3 yr, R1=R (let) and A2 = ₹ 980, R2 = (R+
25
100
‌of‌R) SI is the difference of amount as the time period is same i.e. SI = A2−A1 = 980 - 944 = 36 As the rate is increased by 25%. So, 25% of SI = 36 SI =
36×100
100
= 144 We know that, A = P + SI ⇒ 944 = P + 144 ∴ P = 944 -144 = ₹ 800 To find the rate of interest, SI =