For a solution formed by mixing liquids L and M, the vapour pressure of L plotted against the mole fraction of M in solution is shown in the following figure. Here _L and _M and represent mole fractions of L and M, respectively, in the solution. The correct statement(s) applicable to this system is(are) : [JEE Adv 2017 P1]

The point Z represent vapour pressure of pure liquid M and Raoult’s law is obeyed when _L arrow 0

Attractive intermolecular interactions between L-L in pure liquid L and M-M in pure liquid M are stronger than those between L-M when mixed in solution

The point Z represents vapour pressure of pure liquid L and Raoult’s law is obeyed when _L arrow 1

The point Z represents vapour pressure of pure liquid M and Raoult’s law is obeyed from _l = 0 to _L = 1

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Solutions

Section: Chemistry

Question : 12 of 23

Marks: +1, -0

For a solution formed by mixing liquids L and M, the vapour pressure of L plotted against the mole fraction of M in solution is shown in the following figure. Here

\chi_L

and

\chi_M

and represent mole fractions of L and M, respectively, in the solution. The correct statement(s) applicable to this system is(are) :

[JEE Adv 2017 P1]

The point Z represent vapour pressure of pure liquid M and Raoult’s law is obeyed when $\chi_L \rightarrow 0$
Attractive intermolecular interactions between L-L in pure liquid L and M-M in pure liquid M are stronger than those between L-M when mixed in solution
The point Z represents vapour pressure of pure liquid L and Raoult’s law is obeyed when $\chi_L \rightarrow 1$
The point Z represents vapour pressure of pure liquid M and Raoult’s law is obeyed from $\chi_l = 0$ to $\chi_L = 1$

Validate

Solution:

* Z represent vapour pressure of pure liquid L and as

\chi_L \rightarrow 1

, the given graph is merging with ideal graph of

p_L

. Hence Option (C) is correct

* Since, vapour pressure of liquid

L(p_L)

is higher than the ideal values so L-M interactions are weaker than L-L & M-M interactions. Hence Option (B) is correct choice.

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