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Section:
Chemistry
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© examsnet.com
Question : 11
Total: 23
Pure water freezes at 273 K and 1 bar. The addition of 34.5 g of ethanol to 500 g of water changes the freezing point of the solution. Use the freezing point depression constant of water as
2
K
k
g
m
o
l
−
1
.The figures shownbelow represent plots of vapour pressure (V.P.) versus temperature (T). [molecular weight of ethanol is
46
g
m
o
l
−
1
] Among the following, the option representing change in the freezing point is :
[JEE Adv 2017 P2]
Validate
Solution:
Mole of
C
2
H
5
O
H
=
34.5
46
m
=
34.5
46
×
1000
500
Δ
T
f
=
34.5
46
×
1000
500
×
2
=
3
T
f
°
−
T
f
=
273
−
T
f
=
3
T
f
=
273
−
3
=
270
K
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