Indian Institute of Foreign Trade 2011 Solved Paper

For a number to be divisible by 3, the sum of it's digit should be a multiple of 3. This can be done in two ways. When the number are formed by using either {1, 2, 3, 4, 5} or {0, 1, 2, 4, 5}.
Total 5 digit numbers that can be formed by {1, 2, 3, 4, 5} without repetition =5×4×3×2×1=120
Total 5 digit numbers that can be formed by {0, 1, 2, 4, 5} without repetition =4×4×3×2×1=96
Therefore, total such number =120+96=216. Hence, option D is the correct answer.