Given that ∣x−1∣+∣x−2∣+∣x−3∣≥6Case 1: Whenx>3(x−1)+(x−2)+(x−3)≥6x≥4Therefore, the value of x∈[4,∞)Case 2: When 2<x<3(x−1)+(x−2)−(x−3)≥6x≥6Therefore, no possible value of x in this domainCase 3: When 1<x<2(x−1)−(x−2)−(x−3)≥6x≤−2Therefore, no possible value of x in this domain.Case 3: When x<1−(x−1)−(x−2)−(x−3)≥6x≤0Therefore, the value of x∈(−∞,0]Therefore, the value of x that will satisfy this inequality: x∈(−∞,0]∪[4,∞)Hence, option B is the correct answer.