IBPS Clerk Prelims Model Paper 6

H < B ... (i)
M ≥ B ... (ii)
K = M ... (iii)
Combining (ii) and (iii), we get
K = M>B ⇒ K≥B.
Hence, neither conclusion II (B= K) nor conclusion III (K > B) is true. But, both conclusion I and conclusion II together make a complementary pair. Hence, either conclusion II (B = K) or conclusion III (K > B) is true.
Again, combining all (i), (ii) and (iii), we get
K=M>B>H ⇒ K>H (conclusion I). Hence, conclusion I (K > H) is true.