D > N ...(i) N=V ...(ii) W < V ...(iii) Combining (i) and (ii), we get D>N = V ⇒ D>V. Hence, conclusion III (V = D) is not necessary true. Again, combining all (i), (ii) and (iii), we get D>N = V>W ⇒ D>W. Hence, neither conclusion I (D = W) nor conclusion II (W < D) is true. But both conclusion I (D = W) and conclusion II (W < D) together make a complementary pair. Hence, either conclusion I or conclusion II is true.