Given equation is x3+x+1=0 On comparing with x3+p1x2+p2x+p3=0, we get ‌p1=0,p2=1,p3=1 ‌‌ Now, ‌‌‌S1=0,S0=2 ‌S2+0⋅S1+2=0‌‌⇒S2=−2 ‌S3+0⋅S2+1⋅S1+(2)=0⇒S3=−2 ‌S4+0⋅S3+1⋅S2+1⋅S1=0 ‌⇒‌‌S4+0+1(−2)+1(0)=0 ‌S4=2 ‌