Given equation is x3+2x2−4x+1=0 Let α,β and γ be the roots of the given equation ∴‌α+β+γ‌=−2,αβ+βγ+γα=−4 ‌ and ‌‌αβγ‌=−1 Let the required cubic equation has the roots 3α,3β and 3γ. 3α+3β+3γ‌=−6, 3α⋅3β+3β⋅3γ+3γ⋅3α‌=−36 and 3α⋅3β⋅3γ‌=−27 ∴ Required equation is ‌x3−(−6)x2+(−36)x−(−27)‌=0 ⇒‌‌x3+6x2−36x+27‌=0