Give word VARIABLE A twice and other are different arrangement of three letter words. Case 12 alike 1 distinct =1C1×6C1×
3!
2!
=6×3=18 Case II All are distinct 7C3×3!=35×6=210 ∴ Total =210+18=288 n(S)=288 Middle letter is consonant. Case I All are distinct =6×4×5=120 Case II When both side a =1×4=4 Total favourable case =120+4=124 ∴ Required probability =
