Let P(x,y) be any point on the circle, therefore it will satisify the circle (x1−3)2+(y1+2)2=5r2 ...(i) The length of tangent drawn from point P(x1,y1) to the circle (x−3)2+(y+2)2=r2 is √(x1−3)2+(y1+2)2−r2=√5r2−r2 [from Eq. (i)] =√4r2=2r According to the question, 16=2r ⇒ r = 8 ∴ Area between two circles =5πr2−πr2 =4πr2=4π.82 =256π sq units