(x−4) y−3=x−4 x−y=1 ...(i) Equation of diameter 2x−y=2 ...(ii) Solving Eqs. (i) and (ii), we have coordinate of centre of circle ∴ x=1,y=0 Centre of Circle (1,0) Radius of circle = distance between (1,0) and (2,1) =√(2−1)2+(1−0)2=√2 Radius =√2 ∴ Equation of circle (x−1)2+(y−0)2=(√2)2 ⇒x2+y2−2x−1=0