Let the inner radius and outer radius be r cm and R cm respectively. The width of the path will be (R−r)cm Difference between the circumference of the outer and inner circle =144cm ⇒2πR−2πr=144 ⇒2π(R−r)=144 ⇒R−r=(144×7)∕44 ⇒R−r=22.9≈23 ∴ The width of the path is 23 cm .