As we see in the figure, Let, side of the square =acm. ∴ length of the rectangle =(a+4)cm. Breadth of the rectangle =(a−3)cm. According to problem, ⇒a2=(a+4)(a−3) ⇒a2=a2+4a−3a−12 ⇒a=12 ∴ length of the rectangle =12+4=16cm. Breadth of the rectangle =12−3=9cm. ∴ Perimeter of the rectangle =2×(16+9)=50cm.