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NCERT Class XII Mathematics Chapter - - Solutions

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Exercise - 7.4
Integrate the functions in Exercises 86 to 108.
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Question : 86 of 271
Marks: +1, -0
3x2x6+1\frac{3x^2}{x^6+1}
Solution:  
Let I=3x2x6+1dxI = \frac{3x^2}{x^6+1} dx
Put x3=t⇒3x2dx=dtx^3 = t \Rightarrow 3x^2 dx = dt
∴I=∫dtt2+1=tan⁡−1t+C\therefore I = \int \frac{dt}{t^2+1} = \tan^{-1} t + C =tan⁡−1(x3)+C.= \tan^{-1}(x^3) + C.
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