Given equation is x – 7y + 5 = 0 ... (i) Slope of this line = $\frac{1}{7}$ ∴ Slope of any line perpendicular to the line (i) is –7 and passes through (3, 0) then y – 0 = –7(x – 3) [Q Product of slope of perpendicular lines is –1] ⇒ y = –7x + 21 ⇒ 7x + y – 21 = 0, is the required equation of line