We have given an equation of line 3x – 4y + 2 = 0 ... (i) Slope of the line (i) = $\frac{3}{4}$ Thus, slope of any line parallel to the given line (i) is $\frac{3}{4}$ and passes through (–2, 3), then its equation is y - 3 = $\frac{3}{4}$ (x (- 2)) ⇒ 4y - 12 = 3x + 6 ⇒ –4y + 12 + 3x + 6 = 0 ⇒ 3x – 4y + 18 = 0