Since, ends of major axis (±3, 0) lie on x-axis. ∴ The equation of ellipse in standard form is $\frac{x^2}{a^2}+\frac{y^2}{b^2}$ = 1 Now, ends of major axis = (±3, 0) ⇒ a = 3. Also, ends of minor axis = (0, ±2) ⇒ b = 2 Hence, required equation of ellipse is $\frac{x^2}{9}+\frac{y^2}{4}$ = 1.