Clearly, the foci (±4, 0) lie on x-axis. ∴ The equation of ellipse in standard form is $\frac{x^2}{a^2} + \frac{y^2}{b^2}$ = 1 Now, vertices are (± 6, 0) ⇒ a = 6, foci are (± 4, 0) ⇒ c = 4 Also, we know that $c^2$ = $a^2 - b^2$ ∴ $(4)^2$ = $(6)^2 - b^2$ ⇒ $b^2$ = 36 – 16 = 20. Hence, the required equation of ellipse is $\frac{x^2}{36} + \frac{y^2}{20}$ = 1.