Since, ends of major axis (0, ± $\sqrt{5}$) lie on y-axis. ∴ The equation of ellipse in standard form is $\frac{x^2}{a^2} + \frac{y^2}{b^2}$ = 1 Now, ends of major axis =(0,± $\sqrt{5}$) ⇒ a = $\sqrt{5}$ Ends of minor axis = (± 1, 0) ⇒ b = 1 Hence, required equation of ellipse is $\frac{x^2}{a} + \frac{y^2}{5}$ = 1