Xavier Aptitude Test 2023 Paper

Let the positive integers Raju & Sarita chose be 'r' & 's'.After doing the given operations, the final numbers they get are $\; \frac{2r-20}{5} \& \; \frac{2s-20}{5}$Adding results we get, $\; \frac{2r-20}{5} + \; \frac{2s-20}{5} = 16$$\; 2r-20+2s-20 = 80$$\; 2r+2s = 80+40+40 = 120$$\; r+s = 60$For maximum value of $\mid r$-s|, one of ' $r$ ' & 's' has to be maximum and other has to be minimum.As $r \& s$ are positive integers minimum value they can take is " 1 ".If $r=1$, then $s=59$$|r-s| = |1-59| = 58$If $s=1$, then $r=59$$|r-s| = |59-1| = 58$Hence maximum value of $|r-s|$ is 58 . Option B is correct.