Let speed of deer =5‌steps‌per‌second and speed of tiger =6‌steps‌per‌second Let deer cover 1m in a step ⇒ tiger covers
2
3
m in a step Hence speed of deer =5m‌per‌second and speed of tiger =6×
2
3
m‌per‌second = 4m‌per‌second Hence time taken by a deer to catch tiger =40‌seconds Distance traveled by deer in 40‌seconds=5×40=200‌steps