Xavier Aptitude Test 2016 Paper

(d)AB = 600 metres. Assume D is midpoint of AB
∠CAB=∠CBA=30°
∴CA=CB,ACD is right angled triangle
∴ AC=

300×2

√3

=200√3= CB
Now from statement I :
CE=10×

5

18

×180=500 m
Let F⊥AE,∠ACF=30°&∠CAF=60°
∴ CF=300 metres (CF= AD)
∠ECF==cos−1

CF

CE

=cos−1

300

500

So, we can get the value of ΔECF, the new angle.
Statement II :
CE = 200√3 = CA
Then ΔECF = 30°, which is different from the anglefound using statement I.
Hence both the statement are inconsistent to each other.