Xavier Aptitude Test 2012 Paper

(b) Let $l$ and $b$ be the length and breadth of the plot. Perimeter of the remaining land $=2[2 b-l+l-b]=2 b$ Perimeter of original land $=2(l+b)$ $\therefore$ Given $\frac{2b}{2(l+b)} = \frac{3}{8}$ $8b = 3l + 3b$ $5b = 3l$ This can be possible if we choose $l=5$ and $b=3$ $\therefore$ Area of land $=15$ sq. units cost of land $=1000 \times 15$ Now, selling price of small and big squares are $9 \times 1200$ and $4 \times 1150$ respectively.Let be sells the remaining land at $\$ x$ per sq. ft. Hence, $\ 2 x=1100$ $x = 550$ Hence option (b)