(b) Let Ram replaces x litres of 12% sol. with 39% solution.Now, quality of 12% sol. in 27 litre =10027×12​∴ After replacing we have volume of 12% sol. =(10027×12​−10012x​+10039x​)=100324+27x​ This will be equal to 27 litre of 21% sol. ∴100324+27x​=10021×27​∴x=27567−324​=27243​=9 Hence option (b)