(b) Let the potter has x pots and he gave it to his two sons.
After selling they received Rs.
x ‌2 . Now, Price of banana chips is less than Rs. 10. Hence
x‌2 will not be a multiple of 100.
Assume they purchased y packets of – potato chips.
Hence
( ) packets.
Hence y is odd.
Let
z be the price of banana chips. Hence they have Rs.
(y×10+z) As
y is odd so
(10y+z) is also odd.
Now, each brother can have equal money if total money earned by them is even.
Hence,
z must be Even.
From this we get
x2=10y+z, This given x cm Even. Now if units digit of
x is 2 or 8, then ten’s place of
x2 will be Even which is not possible.
Hence unit digit of
x is 4 or 6. So, unit digit of
x2 must be 6.
∴ z = 6
Hence son having banana chips owes
Rs.[(y−1)×+6 ] and other son owes
[(y+1)× ] Hence, one of the son has
Rs.[(y+1)×]− [ ( )×10+6 ] = Rs. 4 more than the other
So, in order to equalize financially be must give Rs. 2 to theother.