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WBJEE 2024 Physics & Chemistry Paper
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© examsnet.com
Question : 71
Total: 80
When a convex lens is placed above an empty tank, the image of a mark at the bottom of the tank, which is 45 cm from the lens is formed 36 cm above the lens. When a liquid is poured in the tank to a depth of 40 cm , the distance of the image of the mark above the lens is 48 cm . The refractive index of the liquid is
1.353
1.544
1.472
1.366
Validate
Solution:
Here we will apply the lens formula and concept of refractive index.
By this formula,
‌
‌
1
v
−
‌
1
u
=
‌
1
f
‌
⇒
‌
1
36
−
‌
1
−
45
=
‌
1
f
‌
⇒
‌
5
+
4
180
=
‌
1
f
‌
⇒
‌
9
180
=
‌
1
f
‌
⇒
f
=
20
‌
cm
Now, when tank is filled with water,
u
=
−
(
5
+
‌
40
µ
)
By lens formula,
‌
‌
1
v
−
‌
1
u
=
‌
1
f
‌
⇒
‌
1
48
+
‌
1
5
+
‌
40
µ
=
‌
1
20
‌
⇒
‌
µ
5
µ
+
40
=
‌
1
20
−
‌
1
48
‌
⇒
‌
µ
5
µ
+
40
=
‌
12
−
5
240
=
‌
7
240
‌
⇒
240
µ
=
35
µ
+
280
‌
⇒
205
µ
=
280
‌
⇒
µ
=
‌
280
205
=
‌
56
41
=
1.366
Hence,
µ
=
1.366
© examsnet.com
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