{\PhCHO}+ {\CH}_3 {\CH}_2- \stackrel{||^{O}{\C}}- {\O}- \stackrel{||^{O}{\C}}- {\CH}_2 {\CH}_3\stackrel{\CH_3\CH_2-\C^{||↖{\O}{───\xrightarrow}-\ONa}_{(\anhydrous)}P The product 'P' in the above reaction is

Correct Answer is : Ph−CH=CH3|C−COOH

\Ph-\CH= \C^{|↖{ \CH_3}}- {\COOH}

{\PhCH}= {\CH}- {\CH}_2- \stackrel{||^{\O}{\C}}- {\O}- \stackrel{||^{\O}{\C}}- {\CH}_2 {\CH}_3