0 at all points f"(x) Solution: f(0) = f(1) = 0 By Rolle’s theorem f'(c) = 0 for some c ∈ (0,1) Now, f'(0) = f'(c) = 0. Again by Rolle’s theorem f"(c_1 ) = 0 c _1\in(0,c)" >

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WBJEE 2020 Math Solved Paper

Question : 49

Total: 75

Let f : R → R be twice continuously differentiable (or f" exists and is continuous) such that f(0)=f(1)=f′(0)=0. Then

f"(c) = 0 for some c ∈ R
there is no point for which f"(x) = 0
at all points f"(x) > 0
at all points f"(x) < 0

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