If we take f(x)=4x4,then (i) f(x) is continuous in (−2,2) (ii) f(x) is differentiable in (−2,2) (iii) f(−2)=f(2) So, f(x)=4x4 satisfies all the conditions of Rolle’s theorem therefore ∃ a point c such that f'(c) = 0 ⇒16c3=0⇒c=0∈(−2,2)