Let Q(x,y,z) be any point which is equidistant from A(0,2,3) and B(2,−2,1), then QA=QB Squaring both sides, we get QA2=QB2 ‌⇒√(x−0)2+(y−2)2+(z−3)2 ‌=√(x−2)2+(y+2)2+(z−1)2‌ (Using distance formula) ‌ ‌⇒4x−8y−42+4=0⇒x−2y−2+1=0 ‌⇒x−2y−1=0 Hence, the required locus is x−2y−1=0