Test Index

VITEEE 2019 Paper

Section: Mathematics

Question : 83 of 125

Marks: +1, -0

x^2 + y^2 - 8x - 4y + c = 0

(-3,2)

, then the coordinates at the other end are

Solution:

The centre of the given circle is C = (4, 2)

Let A = (-3, 2)

If (α, β) are the coordinates of the other end of the diameter, then, as the middle point of the diameter is the centre,

\therefore \frac{\alpha-3}{2}=4

and

\frac{\beta+2}{2}=2

\Rightarrow \alpha=11, \beta=2

Thus, the coordinates of the other end of diameter are (11,2)

Go to Question:

Prev Question

Next Question