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VITEEE 2017 Paper
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Section:
Chemistry
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© examsnet.com
Question : 64
Total: 125
Iron crystallizes in several modifications. At about 911 °C, the bcc ’ a ’ form undergoes a trasition to fcc ’ γ ’ form. If the distance between the two nearest neighbours is the same in the two forms at the transition temperature, the ratio of the density of iron in fee form (
ρ
2
) to that of iron of bcc form (
ρ
2
) at the transition temperature
ρ
1
ρ
2
= 0.918
ρ
1
ρ
2
= 0.718
ρ
1
ρ
2
= 0.518
ρ
1
ρ
2
= 0.318
Validate
Solution:
In α - form distance between nearest neighbour atom is
√
3
a
1
2
In γ form distance between nearest neighbour atom is
a
2
√
2
∴
√
3
a
1
2
=
a
2
√
2
(given)
or
a
2
a
1
=
√
3
2
ρ
1
ρ
2
=
z
1
z
2
(
a
2
a
1
)
3
=
1
2
(
√
3
2
)
3
= 0.918
© examsnet.com
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