Let the line be ax​ = by​ = cz​ ... (i) If line (i) intersects with the line 2x−1​ = 4y+3​ = 3z−5​ , then ​a24​b4−3​c314​​ = 0 ⇒ 9a - 7b - 10c = 0 ... (ii) from (i) and (ii), we have 1a​ = −3b​ = 5x​ ∴ The line is 1x​ = −3y​ = 5z​