Given sphere is x2+y2+z2 - 6x - 12y - 2z + 20 = 0 Centre = (3,6, 1) Here, one end of diameter is (2, 7, 3). Let the other end of the diameter be (x, y, z) Centre of the sphere will be the mid-point of the ends of diameter. So , (3 , 6 , 1) = (
2+x
2
,
7+y
2
,
3+z
2
) ⇒ 2 + x = 6 ⇒ x = 4 ⇒ 7 + y = 12 ⇒ y = 5 and 3 + z = 2 ⇒ z= - 1 Therefore, (x, y, z) = (4, 5,-1)