Since axes are perpendicular so mid point lies on axial line of one magnet and on equitorial line of other magnet ∴ B1 = 4πd3μ02M = 1310−7×2×1 = 2 × 10−7 T and B2 = 4πd3μ0M = 1310−7×1 = 10−7 T As B1 ⊥ B2 ∴ Resultant magnetic field = B12+B22 = 5 × 10−7 T