Test Index

VITEEE 2009 Paper

Question : 42 of 120

Marks: +1, -0

Solution:

In Wacker process, alkene is oxidised into aldehyde.

\mathrm{CH}_2=\mathrm{CH}_2+\frac{1}{2}\mathrm{O}_2\xrightarrow[\mathrm{H}_2\mathrm{O}]{\mathrm{PbCl}_2\cdot\mathrm{CuCl}_2}\mathrm{CH}_3\underset{(B)}{\mathrm{CHO}}

Since only alkenes produce aldehydes, on ozonolysis, hence 'A' must be an alkene.

Now to find the structure of alkene we should add two molecules of aldehyde and replace O by double bond.

Therefore, alkyne must be

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