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UPTET Paper 1 2021 Solved Paper

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Question : 104 of 150

Marks: +1, -0

The value (0.00032)^{0.6} is

0.060
0.008
0.860
0.842

Solution:

Concept:

Rewrite the decimal as a fraction and simplify the exponent using laws of exponents.

Explanation:

Write

0.00032

as

\frac{32}{100000} = \frac{2^5}{10^5} = \left(\frac{2}{10}\right)^5 = \left(\frac{1}{5}\right)^5

.

The exponent

0.6

is

\frac{6}{10} = \frac{3}{5}

.

So

(0.00032)^{0.6} = \left[\left(\frac{1}{5}\right)^5\right]^{\frac{3}{5}} = \left(\frac{1}{5}\right)^{5 \times \frac{3}{5}} = \left(\frac{1}{5}\right)^3 = \frac{1}{125} = 0.008

.

Answer:

B. 0.008

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