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UPTET Paper 1 2013 Solved Paper

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Question : 104 of 150

Marks: +1, -0

The value of

[{((-2)^{-1})^{-1}}^{-1}]^{-1} is

$-2$
2
1
16

Solution:

Concept:

n^{-1} = \frac{1}{n}

. Raising a power to a power multiplies the exponents. Work from the innermost bracket outward.

Explanation:

Start with

(-2)^{-1} = \frac{1}{-2} = -\frac{1}{2}

.

Then

\left((-2)^{-1}\right)^{-1} = \left(-\frac{1}{2}\right)^{-1} = -2

.

Next

\left[\left((-2)^{-1}\right)^{-1}\right]^{-1} = (-2)^{-1} = -\frac{1}{2}

.

Finally

\left[\left[\left((-2)^{-1}\right)^{-1}\right]^{-1}\right]^{-1} = \left(-\frac{1}{2}\right)^{-1} = -2

.

Answer:

-2

(Option A)

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