6C(g)+3H2(g) → C6H6 ; ΔHexp = - 358 kJ ΔHf can also be calculated as ΔHf(C6H6) =
[6×ΔHC(s)→C(g)+3×ΔHH−H]
= [3 BE of C = C + 3 BE of C = C + 6 BE of C - H] = [6 × 716.8 + 3 × 436.9] - [3 × 340 + 3 × 620 + 6 × 490] ΔHresonance = ΔHf(exp)−ΔHf(calc) = - 358.5 - (- 208.5) = - 150 kJ mol−1