The equation of plane passing through (1, 1, 2) is A(x - 1) + B(y - 1) + c(z - 2) = 0 ...(i) Now, It is perpendicular to x - y + 2 = 2 and x + y - 2z = 4. ∴ A - B + C = 0 A + B - 2c = 0 ⇒
A
|
−1
1
1
−2
|
=
B
|
1
1
−2
1
|
=
C
|
1
−1
1
1
|
Substitute the value of A, B and c is equation (1) 1(x - 1) + 3(y - 1) + 2(z - 2) = 0 ⇒ x + 3y + 2z = 8 Distance of this plane form (2, 2, 1) is given by d = |