Key-Idea The change in entropy of a system is given as ΔS=
ΔQ
T
where, T= temperature and ΔQ= heat absorbed by the system. Here, latent heat of ice, L=80cal∕g, mass of water, m=10g and temperature, T=0°C=273K Heat given to 10g ice, E=mL=10×80 ⇒E=800cal So, the entropy change Δs=
E
T
=
800
273
⇒Δs=2.93cal∕K Hence, the correct option is (b).