Given f(x)=2x3−3x2−12x+6 As we know that Point c from the domain of the function y = f(x) is called stationary point of the function y =f(x)iff′(c)=0 First find f′(x). f′(x)=6x2−6x−12 Now, f’(x)=0 ⇒6x2−6x−12=0 ⇒(x−2)(x+1)=0 ⇒ x = 2 and x = - 1 ∴ Stationary point of the function are 2 and -1