Concept:Use the identity a3+b3+c3−3abc=(a+b+c)(a2+b2+c2−ab−bc−ca).Here, set a=x, b=−y, c=−z so that the expression becomes x3−y3−z3−3xyz.Explanation:Convert each binary number to decimal:x=(1111)2=1⋅23+1⋅22+1⋅21+1⋅20=15y=(1001)2=1⋅23+0⋅22+0⋅21+1⋅20=9z=(110)2=1⋅22+1⋅21+0⋅20=6Now compute a+b+c=x−y−z=15−9−6=0.Since a+b+c=0, the entire product (a+b+c)(…) is zero.Thus x3−y3−z3−3xyz=0.In binary, 0 is written as (0)2.Answer:D. (0)2